-0.000125x^2+0.04x-2.442=0.5

Solution for -0.000125x^2+0.04x-2.442=0.5 equation:

-0.000125x^2+0.04x-2.442=0.5

We move all terms to the left:

-0.000125x^2+0.04x-2.442-(0.5)=0

We add all the numbers together, and all the variables

-0.000125x^2+0.04x-2.942=0

a = -0.000125; b = 0.04; c = -2.942;
Δ = b2-4ac
Δ = 0.042-4·(-0.000125)·(-2.942)
Δ = 0.000129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.04)-\sqrt{0.000129}}{2*-0.000125}=\frac{-0.04-\sqrt{0.000129}}{-0.00025}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.04)+\sqrt{0.000129}}{2*-0.000125}=\frac{-0.04+\sqrt{0.000129}}{-0.00025}
$